The point of the concurrence of all angle bisectors of a triangle is called the?
2 answers:
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Answer:
-2.5x-.5
draw the dotted line (3/7)x-3 and shade below it
Step-by-step explanation:
First, we need the slope
Use the slope formula:
so we have
y= -2.5x+b
Solve for b by plugging in coordiantes
-8= -2.5(3)+b
-8= -7.5+b
b= -.5
Put it together and get -2.5x-.5
2.)
A line is parallel to another line if they have the same slope (and different y intercepts)
So in the formula y=mx+b we knowe that m= 2/3
Now it's just a matter of solving for B
plug in the required coordinate to do this
-1=(2/3)*0+b
-1= b
Put it all together to get
3.)
put this into slope intercept form
3x-7y>21
3x-21 > 7y
(3/7)x-3 >y
To graph this just draw a dotted line with the equation (3/7)x-3 and shade everything below it (use de_smos if you're stuck)