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Olin [163]
3 years ago
13

7th grade math help me pleaseee

Mathematics
2 answers:
RUDIKE [14]3 years ago
6 0

Answer:

whered all the time go? :(

Step-by-step explanation:

Rufina [12.5K]3 years ago
5 0

Answer:

A. 6.25x + 7.50 = 26.25

Step-by-step explanation:

Clara paid 7.50 for an admission ticket, each round was 6.25 and she did it for x rounds. 6.25x is the same thing as 6.25 times x rounds.

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Write the augmented matrix for each system of equations.
Fudgin [204]

<u>We are given the equations: </u>

10x = 10

-5x - 8y = 9

Since we don't have a coefficient of y in the first equation, we will rewrite the first equation as:

10x + 0y = 10

<u>Writing an Augmented matrix for the 2 equations:</u>

10x + 0y = 10

-5x - 8y = 9

\left[\begin{array}{ccc}10&0|&10\\-5&-8|&9\end{array}\right]

5 0
3 years ago
A ladder leaning against a wall makes an angle of 45º with the ground. If the length of the ladder is 20 feet, find the approxim
Sveta_85 [38]

Answer:The way to answer this would be to show you a calculator's answer

Step-by-step explanation:

https://www.calculator.net/triangle-calculator.html?vc=45&vx=&vy=20&va=90&vz=&vb=45&angleunits=d&x=62&y=20

6 0
3 years ago
Cd an anyone help me pls
Burka [1]

Answer:

ITS FALSE

CAN I PLEASE GET BRAINLIEST IM TRYING TO RANK UP THANKSS <3

Step-by-step explanation:

3 0
2 years ago
Q‒1. [5×4 marks] a) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6? (150) b) How many three-
amid [387]

Answer:

a) 294

b) 180

c) 75

d) 174

e) 105

Step-by-step explanation:

I assume that for each problem, the first digit can't be 0.

a) There are 6 digits that can be first, 7 digits that can be second, and 7 digits that can be third.

6×7×7 = 294

b) This time, no digit can be used twice, so there are 6 digits that can be first, 6 digits that can be second, and 5 digits that can be third.

6×6×5 = 180

c) Again, each digit can only be used once, but this time, the last digit must be odd.

If only the last digit is odd, there are 3×3×3 = 27 possible numbers.

If the first and last digits are odd, there are 3×4×2 = 24 possible numbers.

If the second and last digits are odd, there are 3×3×2 = 18 possible numbers.

If all three digits are odd, there are 3×2×1 = 6 possible numbers.

The total is 27 + 24 + 18 + 6 = 75.

d) If the first digit is 3, and the second digit is 3, there are 1×1×6 = 6 possible numbers.

If the first digit is 3, and the second digit is greater than 3, there are 1×3×7 = 21 possible numbers.

If the first digit is greater than 3, there are 3×7×7 = 147 numbers.

The total is 6 + 21 + 147 = 174.

e) If the first digit is 3, and the second digit is greater than 3, then there are 1×3×5 = 15 possible numbers.

If the second digit is greater than 3, there are 3×6×5 = 90 possible numbers.

The total is 15 + 90 = 105.

6 0
3 years ago
Lines of symmetry give e the answer
quester [9]

Answer:

4

Step-by-step explanation:

There are 4 reflectional symmetry

6 0
2 years ago
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