Find value of z pls help:)

To rent a certain meeting room, a college charges a reservation fee of $18 and an additional fee $5 of per hour. The chemistry c

julsineya [31]

Answer:

You need the minimum cost for renting the meeting room given the following info

Reservation Fee = $18

Hourly Rate = $5

The renter wants to keep the cost below $58

So the cost will vary with the time, t you use the inequality below

5t + 18 ≤ 58

You can solve this to get that minimum

You can check you answer by graphing it.

I hope this helps!<3

3 0

2 years ago

PLEASE HELP!!! WILL MARK BRAINLIEST!!! CAN you help there is a website it has the answers appealy but I cannot seem to find them

miv72 [106K]

Answer:

The difference is While pay grades are administrative classifications used primarily to standardize compensation across the military services, ranks indicate a level of responsibility (for personnel, equipment, and mission) which grows with each increase in rank.

Step-by-step explanation:

There similar because Pay grades E-1 through E-3 generally indicate basic training, advanced training or entry-level work. For the Army and Marines, E-1 corresponds to the rank of private

I hoped this helped!

3 0

2 years ago

A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn

tester [92]

Answer:

a) We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

b) $z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

c) $p_v =2*P(z$

d) Null hypothesis: $p=0.35$

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

$\hat p=\frac{522}{1562}=0.334$ estimated proportion of people who have heard of a new electronic reader

$p_o=0.35$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Part a

We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

Part b

The statistic for this case is given :

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

$p_v =2*P(z$

Part d

The null hypothesis for this case would be:

Null hypothesis: $p=0.35$

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0

3 years ago

What are all solutions to the differential equation dy/dx=sec^2*x ?

zysi [14]

Answer:

y=tanx+C

Step-by-step explanation:

$\frac{dy}{dx} = {sec}^{2} \: x \\ \\ dy = {sec}^{2} \: x \: dx \\ integrating \: both \: sides \\ \\ \int \:1\: dy = \int {sec}^{2} \: x \: dx \\ \\ \huge \red{ \boxed{ \therefore \: y = tan \: x + c}} \\$

4 0

3 years ago

PLEASE HELP ANYONE PLEASE HELP !!!!

aliya0001 [1]

1. Square

2. (0, 0), (6,3) (6,13),(-0.5,0)

4 0

3 years ago

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