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sertanlavr [38]
3 years ago
15

Find value of z pls help:)

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

80000000

Step-by-step explanation:

78=897

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The air pressure inside Jason’s bike tires decreases by about 6% each week. The original pressure was 45 pounds per square inch
Brrunno [24]
Compound percentage reduction can be calculated by multiplying the initial number by (1-x)^t where x is the percentage reduction (/100, i.e. 1% reduction is 0.01), and t is the number of times it has reduced.

So:
a) p=45(1-0.06)^t=45*0.94^t
Where t is the number of weeks.

We can then just substitute in to work out the final pressure:
b) p = 45*0.94^6 = 31psi
5 0
3 years ago
Someone please help me figure this question out!!
rosijanka [135]
If you subtract 1.1 from 5.8 you will end up with 4.7
then you subtract 10^7 from 10^8 which will give you 10^1 
then you add the seven back which will give you your answer of 
4.7 10^8
3 0
3 years ago
Which of the following is not a polygon
sp2606 [1]

<u><em>PLEASE PROVIDE AN EXAMPLE!</em></u>

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Without an example, the only thing I can tell you is a Polygon is a plane figure with three straight sides (or more) and angles. (usually 5 or more.)

<em>-</em>

<em>Sorry, This was all I could provide with the amount of information given, please try to provide more information! If you have extra information, please let me know and I'll be sure to help!</em>

7 0
3 years ago
What is 2<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\frac{1}{5}" align="
vivado [14]

2\dfrac{1}{5}+1\dfrac{1}{10}=2+\dfrac{1}{5}+1+\dfrac{1}{10}=(2+1)+\left(\dfrac{1}{5}+\dfrac{1}{10}\right)\\\\=3+\left(\dfrac{1\cdot2}{5\cdot2}+\dfrac{1}{10}\right)=3+\left(\dfrac{2}{10}+\dfrac{1}{10}\right)=3+\dfrac{2+1}{10}=\boxed{3\dfrac{3}{10}}

7 0
3 years ago
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

3 0
2 years ago
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