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Amanda [17]
3 years ago
15

Stem | leaf

Mathematics
1 answer:
dalvyx [7]3 years ago
7 0
Answer: 24

explanation: mode is the value that repeats most often. so, in this case, 24 repeats the most often.
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Brainest for best answer only 5 mins left show your work
liraira [26]

Answer:

b. 61.75

Step-by-step explanation:

Split it into a rectangle and a triangle

1. Rectangle

You can see that the side lengths are 7 and 6.5, so the area is 7 * 6.5 = 45.5

2. Triangle

You know that the base is 6.5 and that the height is 5 (because 12 - 7 = 5) so you can find the area by doing 6.5 * 5 / 2 = 16.25

3. Total

Add the two areas, so 45.5 + 16.25 = 61.75

4 0
3 years ago
Read 2 more answers
Addison brought 5 pounds of oranges and 7 pounds of cherries to make a fruit salad for a fund raiser. She wants to package an eq
igor_vitrenko [27]
This is how i solved this:

9+7=1616 divided by 12 = 1.3 (repeater)1.3 (repeater) = 1 3/10Addison should put 1 3/10 pounds of salad in each container.
7 0
3 years ago
Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang
Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population standard deviation is:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

The information provided is:

<em>n</em> = 26

<em>s</em> = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652

\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}

     =\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0
3 years ago
Which of the following sets of numbers could be the lengths of the sides of a triangle? A. 1 mi, 9 mi, 10 mi B. 8 mi, 9 mi, 2 mi
Svetach [21]

Answer:

Option B. 8 mi, 9 mi, 2 mi

Step-by-step explanation:

The option A doesn't have a set of numbers which could be the lengths of the sides of a triangle. The numbers 1,9,10 mean that the longest side is exactly the sum of the others. The only possible way is they lie in the same line, no triangle is formed

Option C gives the numbers 1,9,11. It's impossible to have a side of 11 when you have the sum of the others less than 11. The maximum extension of the other sides (forming a line) won't be enough to reach the length of 11

Option D is also infeasible for the same reason as the option A. The three lines must be aligned to be connected in its extremes

Option B is the only one who can provide a set of possible lengths of a triangle since the sum of the shortest sides is greater than the third. If we open wide enough the angle between the 2 mi side and the 8 mi side, we would eventually connect the 9 mi side and form a triangle

7 0
3 years ago
What is the area of the sector shown in the picture
tatuchka [14]

Answer:

The area of the sector shown is 4.75 pi

Step-by-step explanation:

First we have to know what fraction of the total circle that part represents

for that we divide 45 ​​by 360

45/360 = 1/8

now we calculate the area of ​​the circle and divide it by 8

a = ( π * 6² ) / 8

a = ( π * 36 ) / 8

a = π * 4.75

a = 4.75 pi

7 0
3 years ago
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