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3 years ago

13

Match the term with the definition

1 answer:

Kobotan [32]3 years ago

4 0

Answer:

line- D

line segment- C

ray- E

point- A

vertex- B

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I don't understand this someone help me :)

Lera25 [3.4K]

Go on line and go one answer my math problems and it will tell you

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4 years ago

Which of the following is the correct factorization of the polynomial below 8x^3+64y^3

dolphi86 [110]

8x^3+64y^3

factor out 8

8(x^3+y^3)

this is known as the sum of cubes

8(x + y) (x^2 - x y + y^2)

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3 years ago

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A universal set U consists of elements. If sets A, B, and C are proper subsets of U and n(U), n(A B)n(A C)n(B C), n(A

iragen [17]

Answer:

$n(A\ u\ B) = 10$

$n(A'\ u\ C) = 10$

$n(A\ n\ B)' = 6$

Step-by-step explanation:

Given

$n(U) = 12$

$n(A\ n\ B) =n(A\ n\ C) = n(B\ n\ C) =6$

$n(A\ n\ B\ n\ C)=4$

$n(A\ u\ B\ u\ C)=10$

Required

Solve a, b and c

There are several ways to solve this; the best is by using Venn diagram (see attachment for diagram)

Solving (a):

$n(A\ u\ B)$

This is calculated as:

$n(A\ u\ B) = n(A) + n(B) - n(A\ n\ B)$

From the attachment

$n(A) = 0+2+4+2 = 8$

$n(B) = 0+2+4+2 = 8$

$n(A\ n\ B) = 4 +2 = 6$

So:

$n(A\ u\ B) = 8 + 8 - 6$

$n(A\ u\ B) = 10$

Solving (b):

$n(A'\ u\ C)$

This is calculated as:

$n(A'\ u\ C) = n(A') + n(C) -n(A'\ n\ C)$

From the attachment

$n(A) = n(U) - n(A) = 12 - 8 = 4$

$n(C) = 0+2+4+2 = 8$

$n(A'\ n\ C) = 2$

So:

$n(A'\ u\ C) = 4 + 8 - 2$

$n(A'\ u\ C) = 10$

Solving (c):

$n(A\ n\ B)'$

This is calculated as:

$n(A\ n\ B)' = n(U) - n(A\ n\ B)$

$n(A\ n\ B)' = 12- 6$

$n(A\ n\ B)' = 6$

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3 years ago

Please help me with this question!!

agasfer [191]

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3 years ago

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ki77a [65]

Im 90% sure it’s H (pls mark as brainliest

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3 years ago

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