Answer:
Given x+y≥4
Let us draw the graph of x+y=4
Put x=0⟹0+y=4⟹y=4
(0,4) is the solution set of x+y=4
Put y=0⟹x+0=4⟹x=4
(4,0) is the solution set of x+y=4
⟹(4,0),(0,4) lies on the line x+y=4
(0,0) lies in the left side area of x+y=4
Let us check that (0,0) lies in the area of solution set of x+y≥4
x+y=0+0<4
⟹(0,0) does not lies in the area of solution set of x+y≥4
∴ solution set is the area which right side of x+y=4
<span>Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept
7x = 14y - 8
7x + 8 = 14y {added 8 to each side}
(1/2)x + (8/14) = y
slope is 1/2
A line perpendicular would have a slope of -2 {the negative reciprocal of 1/2}
#1 y = -2x - 7 {it is the only one with a slope of -2}</span>
Answer:
a) 3y + x
b) a ^ 2 -2b
c) t ^ 4 + m / 2
d) xy - x ^ 2-y ^ 2
Step-by-step explanation:
a) o triplo de um número y adicionado a um número x ______ 3y + x ________
b) a diferença entre o quadrado do número a e o dobro do número b ______ a ^ 2 -2b _____
c) quadruplicar o número t aumentado pela metade o número m _______ t ^ 4 + m / 2 _____
d) a diferença entre o produto do produto do número x e o número y e o quadrado do número
The____xy - x ^ 2-y ^ 2 _____
(5raise to power 5)÷(4)=3125/4)
His answer works ... it gives 150, which is the same as (60 + 90) ... but he didn't deliver exactly what the problem asked for.
It asked for the <u>GCF</u> to be outside the parentheses, and he put '3' there.
'3' is certainly one common factor of 60 and 90, but it's far from being the
greatest one.
The GCF of 60 and 90 is actually 30 . So the absolutely positively technically correct response to the instructions in the problem would be 30(2 + 3).