When car B passes car A, they will have traveled the same distance, d.
speed = distance/time
distance = speed * time
Car A travels t time.
Since car B starts an hour later, car B travels t - 1 time.
Car A:
d = st
s = 40t
Car B:
d = st
d = 60(t - 1)
The distance are equal, so
40t = 60(t - 1)
40t = 60t - 60
-20t = -60
t = 3
Car A started at 9 am.
9 am + 3 hours = noon.
Answer: at noon.
Option b is correct
x=1.75
To solve the problem you must apply the proccedure shown below:
1. You have the following quadratic equation given in the problem:
<span>9x^2+2x-7=0
</span>
2. When you factor it, you obtain:
(9x-7)(x+1)=0
3. Then, you have that the roots of the quadratic equation are:
(9x-7)(x+1)=0
x1=7/9
x2=-1
5^9/5^5= 625
You can either change the exponents to their equivalent whole numbers or subtract exponents.
The answer could also be represented as 5^4