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igomit [66]
3 years ago
14

Illustrate 1/4 of 7 solve this fraction

Mathematics
1 answer:
irakobra [83]3 years ago
4 0
If you would like to solve 1/4 of 7, you can do this using the following steps:

1/4 of 7 = 1/4 * 7 = 7/4 = 1 3/4

The correct result would be 1 3/4.
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TRUE or FALSE: A linear equation written in "slope-intercept form" would look similar to y = mx + b.
Art [367]

Answer:

i believe it would be true

5 0
2 years ago
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7(8+x+2) equals what exactly i dont know ​
Nataly [62]

Answer:

70 + 7x

Step-by-step explanation:

7(8+x+2)

Combine like terms in the parenthesis

7(8+2+x)

7(10+x)

Distribute

70 + 7x

4 0
3 years ago
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find two positive real numbers such that they sum to 108 and the product of the first times the square of the second is a maximu
topjm [15]

The two positive numbers are 36 and 72 which gives a sum equal to 108 and the product of 36 and the square of 72 is a maximum.

Any integer greater than zero is considered a positive number. A positive number can either be written as a number or with the "+" symbol in front of it.

Let us consider the two positive real numbers as x and y. Then, their sum is written as,

x+y=108

Then, y=108-x

And the product is written as,

P=xy²

Substitute value of y in the above equation, we get,

\begin{aligned}P&=x(108-x)^2\\&=x(11664-216x+x^2)\\&=11664x-216x^2+x^3\\&=x^3-216x^2+11664x\end{aligned}

Now, differentiate P with respect to x, and we get,

\begin{aligned}\frac{dP}{dx}&=3x^2-432x+11664\\&=x^2-144x+3888\end{aligned}

Solving the above equation to zero, we get,

\begin{aligned}x^2-144x+3888&=0\\x^2-36x-108x+3888&=0\\x(x-36)-108(x-36)&=0\\(x-108)(x-36)&=0\\x&=\text{108 or 36}\end{aligned}

Substitute values of x in y=108-x, to get values of y.

If we substitute x=108, we get the y value as zero which doesn't give the required solution.

But, if we substitute x=36, we get,

\begin{aligned}y&=108-36\\y&=72\end{aligned}

Thus, the two positive numbers are 36 and 72.

To know more about positive numbers:

brainly.com/question/1635103

#SPJ4

4 0
1 year ago
Choose the pair(s) of integers that can be substituted into the equation ax2 - 6x + c = 0 so that it has two real solutions.
Maksim231197 [3]

The options are not provided, but method is stated below

Answer:

Quadratic equation ax2 - 6x + c = 0

options would be given for a and c

  1. substitute a and c
  2. check for Discriminant
  3.  b^2 - 4ac \geq  0
  4. 36 -4ac \geq 0

These conditions will fetch us the result required among the options.

Note : the \geq sign will give us the result for Two real unequal solutions and two real equal solutions.  If we only need Real unequal solutions we only use > sign instead of \geq

4 0
2 years ago
The width of a swimming pool is one third of its length.The width of the pool is 15 feet.What is the length of the pool?Write an
zubka84 [21]
The answer is 45

Here is why: 15*3=45
5 0
2 years ago
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