Answer:
void printC()
{
int i, j;
for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows
{
printf("C"); //print C for every row
for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows
{
if (i == 0 || i == 4) //For first and last row
printf("C"); //print 'CCCCCCC'
else if (i = 1|| i= 3) //for Second forth row
printf("C + +"); //print 'C + +'
else if (i = 2) For second row
printf("C +++++"); //print 'C +++++'
else
continue; //to jump to next iteration
}
printf("\n"); // print in next line
}
}
Answer:
Boom operator- Microphone
Director of photography- video camera
Art Director- lighting
Gaffer- set building
Answer:yo bro I don’t know but the answer is b
Explanation:
Answer: Windows
Explanation:
ShellShock: Also called Bashdoor, it is a security bug which is found in the Bash shell of operating system e.g. Unix. It allows the hacker to execute scripts and commands by gaining unauthorized access. This affects many machines, devices that use Bash. Servers like web servers are most affected as most of them run Unix based OS like OS X. Most vulnerable are those who use Unix or Linux operating systems.
Microsoft Windows does not use Bash so it does not directly affect Windows os. For those who are using Windows PC, Windows phones and websites that are developed by MS software are non-vulnerable to ShellShock.
Answer:
the second last option
Explanation:
secure HTTP is armed with passwords to ensure that only authorised users gain entry.
the data is encrypted during transmission
