The problem ask to calculate the initial speed of the sled that was shove up a frictionless 28 degree incline and reaches a maximum vertical height of 1.35 m than it started and the initial speed of the sled is 5.14 m/s. I hope you are satisified with my answer
Answer:
25%
Step-by-step explanation:
200-150=50
50/200=0.25
have a nice day!
Answer:
2![\sqrt{34}](https://tex.z-dn.net/?f=%5Csqrt%7B34%7D)
Step-by-step explanation:
Calculate the distance (d) using the distance formula
d = √(x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (4, - 6)
d = ![\sqrt{(4+2)^2+(-6-4)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%284%2B2%29%5E2%2B%28-6-4%29%5E2%7D)
= ![\sqrt{6^2+(-10)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B6%5E2%2B%28-10%29%5E2%7D)
= ![\sqrt{36+100}](https://tex.z-dn.net/?f=%5Csqrt%7B36%2B100%7D)
=
=
=
×
= 2![\sqrt{34}](https://tex.z-dn.net/?f=%5Csqrt%7B34%7D)
The answer is 113.1. Hope this helps
Sorry I don’t know what the answer is