Can I please get some help

Mathematics

1 answer:

harkovskaia [24]3 years ago

4 0

Answer:

Step-by-step explanation:

Area is graph 1

radius is graph 2

Circumference is graph 3

ask if you want to know how I figured those out :)

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PLSSS HELP GIVING BRAINLIEST <br>Find the value of x. 160° (10x + 50) O A. 11 B. 13 O c. 4 D. 21

vekshin1

Answer:

A. 11

Step-by-step explanation:

Since the angles are vertical angles (share a vertex) they are equal in measure.

160 = 10x + 50

subtract 50 from both sides

110 = 10x

divide both sides by 10

x = 11

4 0

3 years ago

Evaluate the line integral in Stokes? Theorem to evaluate the surface integral integrate S ( x F) n dS. Assume that n is in the

gtnhenbr [62]

Answer:

Step-by-step explanation:

Consider that F(x,y,z) = (x + y, y + z, z + z)

$r(t)=(cos t,4sint,\sqt{5}cost)\\r'(t)=(-sint,4cost,-\sqrt{5}sint)\\F(r(t))=[tex]\int\limits^{2\pi}_0 {F(r(t))r'(t)} \, dt \\\\=\int\limits^{2\pi}_0(cost+4sint,4sint+\sqrt{5}cost+cost)(-sint,4cost,-\sqt{5}sint)dt\\\\=\int\limits^{2\pi}_0(-sintcost-4sin^2t+16costsint+4\sqrt{5}cos^2t-5sintcost-\sqrt{5}sintcost)dt\\\\=\int\limits^{2\pi}_0(10sintcost-4sin^2t+4\sqrt{5}cos^2t-\sqrt{5}sintcost)dt\\\\=\int\limits^{2\pi}_0((10-\sqrt{5})sintcost-(4+4+\sqrt{5})sin^2t+4\sqrt{5})dt\\\\(10-\qrt{5})(0)-(4+4+\sqrt{5}(\pi)+4\sqrt{5}(2\pi)\\\\(\sqrt{5}-1)4\pi)$ [/tex]