Answer:
5.33333.....
Step-by-step explanation:
I used symbolab to get my answer make me brainleist pls
The conclusion is valid
it is a systematic random sample
and the second one is a line graph (I think)
Try using Photomath for some it’s easy and faster than waiting for people to respond on here i can help u when I’m done w this test with the left side if ur still stuck
You can show that
by constructing a triangle.
Take two points, O(0, 0) and A(1, 0), and let B be the point on the unit circle such that the angle between the line segments OA and OB is
radians.
Since both A and B lie on the circle, the line segments OA and OB both have length 1 (same as the circle's radius). We finish constructing the triangle by connect A and B.
Since OB and OA have the same length, triangle OAB is isosceles, but more than that, it's also equilateral. Why? Because the interior angles of any triangle always add to
radians. We know one of the angles is
radians, which leaves a contribution of
radians between the remaining angles A and B. Angles A and B must be congruent (because OAB is isosceles), which means they also have measure
radians.
Next, draw an altitude of the triangle through point B, and label the point where it meets the "base" OA, C. Since OAB is equilateral, the altitude BC is also a perpendicular bisector. That means OC has length
, and by definition of
we have
