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3 years ago

Solve the math problem

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

6 0

The second one

Because if you can do live by that you can do that bye-bye

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Aloha! I need help with this! Thanks :)))

White raven [17]

Perimeter: 48
Area: 135

Solve for all the unknown distances and areas by using the values given to you.

4 0

3 years ago

Find an equation in standard form for the hyperbola with vertices at (0, ±4) and asymptotes at y = ±2/3x.

Bezzdna [24]

Check the picture below.

so the hyperbola looks more or less like so, is a hyperbola with a vertical traverse axis, with a = 4 and h = 0, k = 0.

$\bf \textit{hyperbolas, vertical traverse axis } \\\\ \cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h, k\pm a)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ asymptotes\quad y= k\pm \cfrac{a}{b}(x- h) \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{the asymptotes are}}{\pm\cfrac{2}{3}x}\implies \pm\cfrac{2}{3}x=k\pm \cfrac{a}{b}(x- h)~~ \begin{cases} h=0\\ k=0\\ a=4 \end{cases} \\\\\\ +\cfrac{2}{3}x=0+\cfrac{4}{b}(x-0)\implies \cfrac{2x}{3}=\cfrac{4x}{b}\implies 2bx=12x \\\\\\ b=\cfrac{12x}{2x}\implies b=6 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(y-0)^2}{4^2}-\cfrac{(x-0)^2}{6^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{36}=1$

7 0

4 years ago

Solve pls branliest.

galina1969 [7]

Answer:

1. no. 2. yes. 3. no. 4. yes. 5. yes.

Step-by-step explanation:i'll explain how to identify integers.

The integers are ..., -4, -3, -2, -1, 0, 1, 2, 3, 4, ... -- all the whole numbers and their opposites (the positive whole numbers, the negative whole numbers, and zero). Fractions and decimals are not integers. For example, -5 is an integer but not a whole number or a natural number. ... Integers are numbers that do not have a fractional part, including positive and negative numbers and zero. Whole numbers are positive integers and zero. Natural numbers are positive integers and are sometimes called counting numbers. tell me if you need me to explain more.

7 0

3 years ago

Question 18 i will maek the brainliest:)

maksim [4K]

Answer:

Median: 14.6, Q1: 6.1, Q3: 27.1, IR: 21, outliers: none

Step-by-step explanation:

Step 1: order the data from the least to the largest.

2.8, 3.9, 5.3, 6.1, 6.5, 7.1, 12.5, 14.6, 16.4, 16.4, 20.8, 27.1, 28.1, 30.9, 53.5

Step 2: find the median.

The median is the middle value, which is the 8th value in the data set.

2.8, 3.9, 5.3, 6.1, 6.5, 7.1, 12.5, [14.6,] 16.4, 16.4, 20.8, 27.1, 28.1, 30.9, 53.5

Median = 14.6

Step 2: Find Q1,

Q1 is the middle value of the lower part of the data set that is divided by the median to your left.

2.8, 3.9, 5.3, (6.1), 6.5, 7.1, 12.5, [14.6], 16.4, 16.4, 20.8, 27.1, 28.1, 30.9, 53.5

Q1 = 6.1

Step 3: find Q3.

Q3 is the middle value of the upper part of the given data set.

2.8, 3.9, 5.3, 6.1, 6.5, 7.1, 12.5, [14.6], 16.4, 16.4, 20.8, (27.1), 28.1, 30.9, 53.5

Q3 = 27.1

Step 4: find interquartile range (IR)

IR = Q3 - Q1 = $27.1 - 6.1 = 21$

Step 5: check if there is any outlier.

Formula for checking for outlier = $Q1 - 1.5*IR$

Then compare the result you get with the given values in the data set. Any value in the data set that is less than the result we get is considered an outlier.

Thus,

$Q1 - 1.5*IR$

$6.1 - 1.5*21 = -25.4$

There are no value in the given data set that is less than -25.4. Therefore, there is no outlier.

3 0

3 years ago

es is making 141414 jars of honey peanut butter. He wants to use 454545 milliliters (\text{mL})(mL)left parenthesis, start text,

DIA [1.3K]

Answer:

i dont know this man if i did would help

Step-by-step explanation:

8 0

3 years ago