Not sure if that's a multiplication or a composition. It doesn't matter. Both f and g have a domain of all real numbers. The domain of
is the same as the domain of g(x), all real numbers
Answer: all real numbers
Answer: Length = 15 meters
Width = 2 meters
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
Area of a rectangle = l × w
where l = length
w = width
Therefore,
2l + 2w = 34 ...... i
l × w = 30 ........ ii
From equation i
2l + 2w = 34
Divide through by 2.
l + w = 17 ...... iii
Then, l = 17 - w ........ iv
Put equation iv into ii
l × w = 30
(17 - w) × w = 30
17w - w² = 30
w² - 17w + 30 = 0
w² - 15w - 2w + 30 = 0
w(w - 15) - 2(w - 15) = 0
(w - 2) = 0
w = 0 + 2 = 2
w - 15 = 0
w = 0 + 15 = 15
Length = 15 meters
Width = 2 meters
Answer:
Valid Argument
Step-by-step explanation:
An argument is valid if its conclusion follows with certainty from its premises.
Given:
Premise: If it has an engine, I can fix it.
Premise: Cars have engines.
Conclusion: I can fix cars.
The argument is valid since the conclusion follows with certainty from the given premises.
Dividing 3,724 by 6 would equal 620.66666666 repeating. Or 620.667
Hope this helped :)
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
__
We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
