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Sphinxa [80]
3 years ago
6

What are the vertices of the image r(90,0) (BCD)

Mathematics
1 answer:
alexira [117]3 years ago
6 0
A. B'(-3, -3), C'(-1, 4), D'(2, 0)
You might be interested in
Use the Distributive Property to simplify the following expression. a: 4(x+2) b; -5(9+x) c: 7(x-3)
ExtremeBDS [4]
<h3>hello!</h3>

=======================================================

The Distributive Property states the following:-

\longrightarrow\sf{a(b+c)=ab+ac

Where

\longrightarrow\sf{a,~b,~and~c~can~be~either~constants~or~variables}

Now, let's use this property to simplify our expressions.

The first one is

\bigstar{\underline{\boxed{{4(x+2)}}}

Simplify by distributing 4:-

\longrightarrow\sf{4~times~x~+4~times~2}

Add the products:-

\longrightarrow\sf{4x+8}

\rule{250}{2}

Solve the next one:-

\bigstar{\underline{\boxed{\sf{-5(9+x)}}}

Distribute -5 & add the products:-

\longrightarrow\sf{-45-5x}

\rule{250}{2}

Solve the last one:-

\bigstar{\underline{\boxed{7(x-3)}}

Distribute 7:-

\longrightarrow\sf{7x-21}

======================================================

<h3>note:-</h3>

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I'll comment and/or edit my answer :)

7 0
2 years ago
Altitudes $\overline{ax}$ and $\overline{by}$ of acute triangle $abc$ intersect at $h$. if $\angle ahb = 132^\circ$, then what i
Sergio [31]
Answer: 48 degrees

-------------------------------------------------------

See the attached image for a visual of the problem and answer.

Based on the diagram, we have angle AHB = 132 degrees (given) equal in measure to angle XHY since these two angles are vertical angles. 

Angles HYC and HXC are right angles due to the nature of AX and BY being altitudes. Recall that altitudes are segments that go from one vertex to the opposite side and they are perpendicular to the opposite side.

Focus on quadrilateral HXCY. So far, we know that...
Angle XHY = 132 degrees
Angle HYC = 90 degrees
Angle HXC = 90 degrees

The angle we want to find is angle ACB, which is the same as angle YCX. This angle is the missing angle of the quadrilateral HXCY.

For any quadrilateral, the four angles must add to 360 degrees. 

(angle XHY) + (angle HYC) + (angle HXC) + (angle YCX) = 360
(132) + (90) + (90) + (angle YCX) = 360
312 + (angle YCX) = 360
312 + (angle YCX) - 312 = 360 - 312
angle YCX = 48 degrees

Since angle ACB is the same as angle YCX, we can say
angle ACB = angle YCX = 48 degrees

So in summary,
angle ACB = 48 degrees

4 0
4 years ago
A relation is plotted as a linear function on the coordinate plane starting at point e (0, 27)(0, 27) and ending at point f (5,−
kolbaska11 [484]
The slope of the line is calculated using
y2 - y1 / x2 - x1
Substituting the given values
-8 - 27 / 5 - 0 = -7
The rate of change or the slope is -7
And the initial value is the value of y when x is 0. From the first coordinates, the initial value is 27.
5 0
3 years ago
Read 2 more answers
HELP ME PLEASE I'LL MARK YOU THE BRAINEST!!!!!!!!<br> Determine the missing values.
a_sh-v [17]

Answer:

Hi it’s me

Step-by-step explanation:

7is the first one

10 is the second

Nvm you already got the answer cause yo asked this 2 weeks ago anyways hi

7 0
3 years ago
Solve:<br> 4x + 3y = 8<br> 2 - 2y = 13
jenyasd209 [6]

Answer:

x = 49/8, y = -11/2

Step-by-step explanation:

look at the attached picture.

3 0
3 years ago
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