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Alchen [17]
3 years ago
14

Math I will rate brainliest

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer: 89

Step-by-step explanation: Just subtract 102 from 13!

yan [13]3 years ago
6 0

Answer:

150.43 units²

Step-by-step explanation:

The radius of the circle is 13 units. The area of the circle is πr², so the area is 169π. To get the area of the sector, we take the degrees and divide by 360, then multiply by the area.

\frac{102}{360} · 169π is about 150.43.

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There's a formula for that.

KE = (1/2)mv²

... = (1/2)(2000 kg)(30 m/s)²

... = 900,000 kg·m²/s²

... = 900,000 J

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It is helpful to know the relationship between kilograms, meters, seconds, and Newtons or Joules.

1 J = 1 kg·m²/s²

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4 years ago
Carly y = 60x + 40 Janiya y = 50x + 80 After how many weeks will Carly and Janiya have the same amount of money in their money b
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3 years ago
Which point is located at (2, 6)? On a coordinate plane, point A is 6 units to the right and 2 units up. Point B is 6 units to t
kow [346]
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6 0
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Read 2 more answers
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Phantasy [73]

Answer:

Step-by-step explanation:

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6 0
3 years ago
(1CQ) Determine whether the series -8/5+32/25-128/125+... is convergent or divergent.
Ivan

Answer:

The series is convergent answer ⇒ (a)

Step-by-step explanation:

* The series is -8/5 + 32/25 + -128/125 + ........

- It is a geometric series with:

- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5

* The difference between the convergent and divergent

  in the geometric series is :

- If the geometric series is given by  sum  = a + a r + a r² + a r³ + ...

* Where a is the first term and r is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).  

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

* If |r| ≥ 1 then the above geometric series diverges

∵ r = -4/5

∴ IrI = 4/5

∴ IrI < 1

∴ The series is convergent

3 0
4 years ago
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