Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
63
Step-by-step explanation:
2x+54=180
2x=180-54
2x=126
divide each side by two u will get x
Answer:147.77
Step-by-step explanation:17.96+3.15=21.11 and 21.11x7= 147.77
Answer:
C
Step-by-step explanation:
dont remember how I did it but it is right.
Answer:
False
Step-by-step explanation:
Given that a researcher reports that there is a significant difference between two treatments at the .05 level of significance.
This implies we can be 95% confident that for samples of large size randomly drawn from the two treatments the difference would be statistically significant.
Because the test statistic we arrived for difference assuming H0 to be true has a p value less than 5% we conclude there is a significant difference between the averages of the two treatments.
Hence this does not mean that the average score for one treatment is at least 5% higher than the average score for the other treatment.
the given statement is false.
