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Makovka662 [10]
3 years ago
11

20 points and will give brainliest!!

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

C=0.65M+22.65

Step-by-step explanation:

The standard charge includes an initial fee and plus an addditional fee for each mile driven and is given by:

S=0.40M+17.75

The insurance charge is given by:

I=0.25M+4.90

So, the total charge C will be the sum of the standard charge S and the insurance charge I:

C=S+I

Substitute:

C=(0.40M+17.75)+(0.25M+4.90)

Rearrange:

C=(0.40M+0.25M)+(17.75+4.90)

Add:

C=0.65M+22.65

And we have acauired our equation relating C to M!

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GuDViN [60]
The answer would be D
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3 years ago
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aliina [53]
It is true, how??Here is explanation:

Consider a quadrilateral ABCD .Join diagnol AC so two triangles ABC & ACD will form.
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3 0
3 years ago
PLEASE HELP 13 INSTEAD OF FIVE POINTS!!!! I REALLY NEED HELP
devlian [24]
A is what the answer is
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3 years ago
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I will give a brainlest, i promise, please help me with this.​
valkas [14]

Answer:

1) b and m

2) m∠8=m∠6

3) 160°

4)x=60°

Step-by-step explanation:

1) all straight lines sum to 180°

subtract the angles given from 180°

the other angle for b is 25°, while the other angle for m is 155°

so we can see that the angles for both lines are the same, hence they are parallel.

2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4

in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.

3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°

(2x-16)°+(7x+20)°=180°

we get x=20(nearest whole number)

∠CED=7x+20=7(20)+20=160°

4) since we need to show that they are parallel,

(2x+30)°=(4x-90)°

2x-4x=-90-30

-2x=-120

x=60

we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)

I hope u understand it the way I put it.

8 0
2 years ago
Solve for x:<br> 1 1/5x−2 1/3&lt;1/7x+1 1/2
Mashcka [7]

Answer: x

Step-by-step explanation:

1\frac{1}{5}x-2\frac{1}{3}

Add 2\frac{1}{3} on both sides and subtract \frac{1}{7}x on both sides to leave x's on the left side and independent values on the right.

(2\frac{1}{3}-\frac{1}{7}x) +1\frac{1}{5}x-2\frac{1}{3}

1\frac{1}{5}x-\frac{1}{7}x

Solve the fractions.

1(\frac{1}{5}-\frac{1}{7})x

1(\frac{(1)(7)-(5)(1)}{(5)(7)} )x

1(\frac{7-5}{35} )x

1(\frac{2}{35} )x

1\frac{2}{35}x

Convert the mixed fraction 1\frac{2}{35} to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

\frac{37}{35}x

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.

(\frac{35}{37}) (\frac{37}{35})x

x

x

x

5 0
3 years ago
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