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Ksju [112]
3 years ago
15

Stuck trying to solve this, didn’t pay attention :/

Mathematics
2 answers:
netineya [11]3 years ago
7 0
Try c! Hope this helps
Gelneren [198K]3 years ago
6 0

Answer:

Pay attention next time

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What is the answer need it
denis-greek [22]

Answer:

\frac{7}{10} |

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{2}{3} * \frac{10}{10}) + (\frac{7}{10} * \frac{3}{3}) = ?

Complete the multiplication and the equation becomes

\frac{20}{30} + \frac{21}{30}

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{20+21}{30} = \frac{41}{30}

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{41+-20}{30} = \frac{21}{30}

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

\frac{21/3}{30/3} =\frac{7}{10}

Therefore:

\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}|

8 0
2 years ago
F(n) = n² – 3 g(n) = 4n - 1 Find f[g(1)]
SVETLANKA909090 [29]

Answer:

f[g(1)]=6.

Explanation:

Given f(n) and g(n) defined below:

\begin{gathered} f\mleft(n\mright)=n^2-3 \\ g\mleft(n\mright)=4n-1 \end{gathered}

First, we evaluate g(1):

\begin{gathered} g\mleft(1\mright)=4(1)-1 \\ =4-1 \\ g(1)=3 \end{gathered}

Therefore:

\begin{gathered} f\mleft(g(1)\mright)=f\mleft(3\mright) \\ f\mleft(3\mright)=3^2-3 \\ =9-3 \\ =6 \end{gathered}

Therefore, f[g(1)]=6.

8 0
1 year ago
Who can solve this in 1 min 5678÷78
andreev551 [17]

It is 72.7948718

~Hope that helped!~

~Izzy <3

5 0
3 years ago
Which is a factor pair of 72?<br><br>A) 12,6<br><br>B) 14,5<br><br>C)23,4<br><br>D)24,2<br>​
scoundrel [369]

Answer:

the answer is A) 12,6. .

Step-by-step explanation:

.

6 0
3 years ago
A drawing is 12 inches wide and 10 inches long. Joe wants to enlarge each side by a scale factor of 0.3. What will be the area o
Andreyy89

Answer:

Area of the dilation = 10.8 square inches

Step-by-step explanation:

Given the original dimension

Length = 12inches

Width = 10inches

If they are dilated by a factor of 0.3

New length = 0.3 * 12 = 3.6in

New width = 0.3 * 10 = 3in

Area of the dilation = 3.6 * 3

Area of the dilation = 10.8 square inches

3 0
2 years ago
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