All categories

3 years ago

(b) What is the probability that distance exceeds the mean distance by more than 2 standard deviations?

Mathematics

1 answer:

Flura [38]3 years ago

7 0

Answer:

>0.95

Step-by-step explanation:

This probably refers to a normal distribution. In a normal distribution, according to the empirical rule,

68% of observed data falls within 1 standard deviation of the mean

95% falls within 2 standard deviations of the mean

99.7% falls within 3 standard deviations of the mean

In this case, the observed data is distance and the average figure for all observed distances is the mean distance.

So, the probability that a/any distance observed exceeds the mean distance by more than 2 standard deviations is >95%

In other words, the probability is >0.95

You might be interested in

ANSWER BOTH!!! A. An international company has 18,600 employees in one country. If this represents 18.2% of the company's employ

bulgar [2K]

Answer:

A. 102,198 employees

B. $22,120 decrease

$293,880 current value

Step-by-step explanation:

6 0

3 years ago

What is the probability that one of the new parts produced will be over 1.412 cm long?

Aliun [14]

Answer:

Hello

Step-by-step explanation:

3 0

2 years ago

When is a car lease better than a car loan

vovikov84 [41]

When you buy a car you can pay off your auto loan but if you lean a car you have to make payments for life

6 0

3 years ago

Read 2 more answers

If f(x)f(x) is an exponential function where f(-0.5)=27f(−0.5)=27 and f(1.5)=21f(1.5)=21, then find the value of f(0.5)f(0.5), t

vovikov84 [41]

Given:

f(x) is an exponential function.

$f(-0.5)=27$

$f(1.5)=21$

To find:

The value of f(0.5), to the nearest hundredth.

Solution:

The general exponential function is

$f(x)=ab^x$

For, x=-0.5,

$f(-0.5)=ab^{-0.5}$

$27=ab^{-0.5}$ ...(i)

For, x=1.5,

$f(1.5)=ab^{1.5}$

$21=ab^{1.5}$ ...(ii)

Divide (ii) by (i).

$\dfrac{21}{27}=\dfrac{ab^{1.5}}{ab^{-0.5}}$

$\dfrac{7}{9}=b^2$

Taking square root on both sides, we get

$\dfrac{\sqrt{7}}{3}=b$

$b\approx 0.882$

Putting b=0.882 in (i), we get

$27=a(0.882)^{-0.5}$

$27=a(1.0648)$

$\dfrac{27}{1.0648}=a$

$a\approx 25.357$

Now, the required function is

$f(x)=25.357(0.882)^x$

Putting x=0.5, we get

$f(0.5)=25.357(0.882)^{0.5}$

$f(0.5)=23.81399$

$f(0.5)\approx 23.81$

Therefore, the value of f(0.5) is 23.81.

6 0

3 years ago

carmen works at a pet store. To feed 8 cats, she empties four 6-ounce cans of cat food into a large bowl.Carmen divides the food

Y_Kistochka [10]

6 x 4 = 24
each cat will get 3 ounces each :)

4 0

2 years ago

Read 2 more answers