Answer:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29)
And for this case we can use the cumulative distribution function given by:
![P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b](https://tex.z-dn.net/?f=%20P%28X%5Cleq%20x%29%20%3D%5Cfrac%7Bx-a%7D%7Bb-a%7D%2C%20a%20%5Cleq%20x%20%5Cleq%20b)
And using this formula we have this:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29%3D%20%5Cfrac%7B12000-10100%7D%7B14700-10100%7D%3D%200.41)
Then we can conclude that the probability that your bid will be accepted would be 0.41
Step-by-step explanation:
Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:
![X \sim Unif( a= 10100, b =14700)](https://tex.z-dn.net/?f=%20X%20%5Csim%20Unif%28%20a%3D%2010100%2C%20b%20%3D14700%29)
If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29)
And for this case we can use the cumulative distribution function given by:
![P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b](https://tex.z-dn.net/?f=%20P%28X%5Cleq%20x%29%20%3D%5Cfrac%7Bx-a%7D%7Bb-a%7D%2C%20a%20%5Cleq%20x%20%5Cleq%20b)
And using this formula we have this:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29%3D%20%5Cfrac%7B12000-10100%7D%7B14700-10100%7D%3D%200.41)
Then we can conclude that the probability that your bid will be accepted would be 0.41
Picture is too tiny I can’t see
You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number:
5^-1 = 1/5
. . . keep trying those. . .
5^-4 = 1/625
so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625
x = log₅ 5⁻⁴
log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down:
x = -4 is your answer
if the exponent dropping down doesn't make sense to you, you can think of it in another way:
x = log₅ 5⁻⁴
expand the expression so that the exponent moves in front of the log function:
x = (-4) log₅ 5
then, still, log base 5 of 5 simplifies to 1, so you're left with:
x = (-4)1 or x = -4
Answer:
30 degrees
Step-by-step explanation:
The sum of exterior angles = 360 degree
102 + 73 + 67 + 88 + a = 360
330 + a = 360
a = 360 - 330
a = 30 degree.
HOPE THIS HELPED YOU
Answer:
4
Step-by-step explanation:
![4 \sqrt{2} \times \sqrt{2}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B2%7D%20%20%5Ctimes%20%20%5Csqrt%7B2%7D%20)
![4 \sqrt{2 \times 2}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B2%20%5Ctimes%202%7D%20)
![4 \sqrt{4}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B4%7D%20)
![4 \sqrt{2}](https://tex.z-dn.net/?f=4%20%5Csqrt%7B2%7D%20)
![4](https://tex.z-dn.net/?f=4)