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pychu [463]
3 years ago
15

The plant-breeding department at a major university developed a new hybrid boysenberry plant called Stumptown Berry. Based on re

search data, the claim is made that from the time shoots are planted 90 days on average are required to obtain the first berry. A corporation that is interested in marketing the product tests 60 shoots by planting them and recording the number of days before each plant produces its first berry. The sample mean is 92.3 days. The corporation wants to know if the mean number of days is different from the 90 days claimed. What are the correct hypotheses?
a) H0:μ≠90
H1:μ=90
b) H0:μ=90
H1:μ≠90
c) H0:μ=92.3
H1:μ≠92.3
d) H0:p=92.3%
H1:p≠92.3%
e) H0:p=90%
H1:p≠90%
Mathematics
1 answer:
Llana [10]3 years ago
3 0

Answer:

b) H0:μ=90, H1:μ≠90

Step-by-step explanation:

The corporation wants to know if the mean number of days is different from the 90 days claimed.

This means that at the null hypothesis, we test if the mean number is the claimed value of 90, and so:

H_0: \mu = 90

The corporations wants to know if the mean number is different, and thus, at the alternate hypothesis, we test if the mean number is different from 90, that is:

H_1: \mu \neq 90

This means that the correct answer is given by option b.

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Answer:

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Step-by-step explanation:

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3 years ago
PLZZZ HELPPPP ILL MARK BRAINLIEST TO FIRST AND CORRECT ANSWER THAT HAS WORK AND A THX TO SECOND AND CORRECT ANSWER.
vovikov84 [41]

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2 years ago
Jumbo eggs in Australia, on average, are supposed to weigh 68g. Margot is in charge of a quality control test that involves weig
Andrej [43]

Answer:

0.9987 = 99.87% probability that the mean weight of 4 eggs in a package is less than 68.5g

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean weight of 67g and a sample standard deviation of 1g.

This means that \mu = 67, \sigma = 1

Sample of 4

This means that n = 4, s = \frac{1}{\sqrt{4}} = 0.5

What is the probability that the mean weight of 4 eggs in a package is less than 68.5g?

This is the pvalue of Z when X = 68.5. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{68.5 - 67}{0.5}

Z = 3

Z = 3 has a pvalue of 0.9987

0.9987 = 99.87% probability that the mean weight of 4 eggs in a package is less than 68.5g

6 0
3 years ago
Read 2 more answers
What is the minimum angle of rotation (in degrees) that will carry the star onto itself?
zloy xaker [14]

Answer:

When you rotate the regular pentagon \begin{align*}72^\circ\end{align*} about its center, it will look exactly the same. This is because the regular pentagon has rotation symmetry, and \begin{align*}72^\circ\end{align*} is the minimum number of degrees you can rotate the pentagon in order to carry it onto itself.

Step-by-step explanation:

3 0
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jek_recluse [69]

Step-by-step explanation:

Price of Jeans = $78.35

30% coupon = 30% × $78.35 = $23.51

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Total cost of jeans = $78.35 - $23.51 + $4.70 + $0.78 = $60.32

8 0
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