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natita [175]
3 years ago
12

Write the nth term of the following sequence in terms of the first term of the sequence.

Mathematics
2 answers:
ahrayia [7]3 years ago
7 0

<u><em>Answer:</em></u>

<u><em>5120 or 2560.One of these</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>1. 10*2=20</em></u>

<u><em>2. 20*2=40</em></u>

<u><em>3. 40*2=80</em></u>

<u><em>4. 80*2=160</em></u>

<u><em>5. 160*2=320</em></u>

<u><em>6. 320*2=640</em></u>

<u><em>7. 640*2=1280</em></u>

<u><em>8. 1280*2=2560</em></u>

<u><em>9. 2560*2=5120</em></u>

Sever21 [200]3 years ago
6 0

Answer:

2360

Step-by-step explanation:

(One Question..Uhm..nth? I'm assuming Ninth)

10, 20, 40, 80, 160, 320, 640, 1280, 2360

Its just doubling every time

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pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

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3 years ago
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podryga [215]

Answer:

s-c= m  c

Step-by-step explanation:

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2 years ago
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never [62]

Answer:

7, 7.1, √51, 7.2

Step-by-step explanation:

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Step-by-step explanation:

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