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Amanda [17]
3 years ago
15

Roseann had $10. She wanted to buy Simian noodles from Mr. Aguilar. Each bowl of Simian cost $2. How many bowls can she buy with

$10?
Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

She can buy 5 bowls of noodles

Step-by-step explanation:

she has $10

each bowl cost $2

so then you divide 2÷10 which = 5

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Faith is tracking the number of burpees she does at a constant rate. Last
bija089 [108]
This is a unit rate question. We can solve this in chronological order of steps:

Step 1: Write out the beginning for the first unit rate.

Faith completed 60 burpees in 5 minutes last week.

Step 2: Since 60 burpees were completed in 5 minutes, we can divide 60 by 5 to find how many burpees were completed in 1 minute.

60 divided by 5 equals 12.
5 divided by 5 equals 1.

Our fraction for how many burpees Faith did in a minute last week is 12/1. This reduces to 12, meaning that Faith did 12 burpees last week.

Step 3: Find the unit rate for this week.

Faith completed 78 burpees in 6 minutes this week. Because of this, we can divide 78 by 6 to find how many burpees Faith completed this week.

78 divided by 6 equals 13.
6 divided by 6 equals 1.

Our final fraction for how many completed burpees Faith did this week is 13/1, which reduces to 13. Therefore, Faith completed 13 burpees per minute this week.

Your final answer: In terms of separate values, Faith completed 12 burpees per minute last week and 13 burpees per minute this week. If you need help, let me know and I will gladly assist you.
6 0
2 years ago
F(x)= 2/x-2 find (fof) (i)
brilliants [131]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Ronald rents a car from Cheap Rent-a-Car for $25 plus $0.05 per mile. Dixon rents a car
wlad13 [49]

Answer:

750 miles

Step-by-step explanation:

Ronald

Rental fee = fixed cost + variable cost

= $25 + $0.05x

Where x = number of miles

Dixon

Rental fee = fixed cost + variable cost

= $40 + $0.03x

How many miles must they both drive for their rental fees to be the same?

Equate the two equations

$25 + $0.05x = $40 + $0.03x

Collect like terms

0.05x - 0.03x = 40 - 25

0.02x = 15

Divide both sides by 0.02

x = 15 / 0.02

= 750 miles

3 0
3 years ago
Two trucks leave a warehouse at the same​ time, traveling in opposite directions. The rate of the faster truck exceeds that of t
EleoNora [17]

Answer:

Speed of the slower truck = 57.5 miles/hour

Speed of the faster truck = 62.5 miles/hour

Step-by-step explanation:

Using missing information;

Assume;

Speed of the slower truck = a

Speed of the faster truck = a + 5

Distance traveled by the slower truck = d

Distance traveled by the faster truck = 600 - d

So,

a(5) = d ........ Eq1

(a+5)(5) = 600 - d

5a + 25 = 600 - d

So,

5a + 25 = 600 - 5a

10a = 575

a = 57.5

Speed of the slower truck = 57.5 miles/hour

Speed of the faster truck = a + 5

Speed of the faster truck = 57.5 + 5

Speed of the faster truck = 62.5 miles/hour

6 0
3 years ago
NO LINKS! Please help me with this problem
Dafna11 [192]

Answer:

\frac{x^2}{9}+\frac{y^2}{4}=1

Step-by-step explanation:

So an ellipse can be expressed in two different but very similar forms:

<u><em>Horizontal Major Axis:</em></u>

   \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

<u><em>Vertical Major Axis</em></u>:
   \frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1

In both equations the length of the major axis is "2a" and the length of the minor axis is "2b"

In the equation you provided, the major axis is horizontal, and the minor axis is vertical.

So looking at the horizontal length, you can see that it's 6, and since this ellipse has a horizontal major axis, that means 2a=6, which means a=3

Looking at the vertical length, you can see that it's 4, and since the ellipse has a vertical minor axis, that means 2b=4, which means b=2

The last thing to note is that the center of an ellipse is (h, k) in the equation, and since here the center is (0, 0) it's (x-0)^2 and (y-0)^2 in the denominator which is just x^2 and y^2

So let's plug in the values into the equation:

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

(h, k) = (0, 0)

a = 3

b = 2

\frac{x^2}{3^2}+\frac{y^2}{2^2}=1\\\\\frac{x^2}{9}+\frac{y^2}{4}=1

7 0
2 years ago
Read 2 more answers
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