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3 years ago

Ronald rents a car from Cheap Rent-a-Car for $25 plus $0.05 per mile. Dixon rents a car

Mathematics

1 answer:

wlad13 [49]3 years ago

3 0

Answer:

750 miles

Step-by-step explanation:

Ronald

Rental fee = fixed cost + variable cost

= $25 + $0.05x

Where x = number of miles

Dixon

Rental fee = fixed cost + variable cost

= $40 + $0.03x

How many miles must they both drive for their rental fees to be the same?

Equate the two equations

$25 + $0.05x = $40 + $0.03x

Collect like terms

0.05x - 0.03x = 40 - 25

0.02x = 15

Divide both sides by 0.02

x = 15 / 0.02

= 750 miles

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Answer:

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3 years ago

Factorize (X + 2 y)square - (2 x minus y) square

gulaghasi [49]

Answer:

- (x - 3y)(3x + y)

Step-by-step explanation:

Given

(x + 2y)² - (2x - y)² ← expand both parenthesis using FOIL

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= x² + 4xy + 4y² - 4x² + 4xy - y² ← collect like terms

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product = 3 × - 3 = - 9 and sum = - 8

The factors are - 9 and + 1

Use these factors to split the xy- term

3x² - 9xy + xy - 3y² ( factor the first/second and third/fourth terms )

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= (x - 3y)(3x + y)

Thus

(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)

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3 years ago

What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the

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The sum of all the measurements is just the average times the number.

$\bar x = \frac{1}{n} \sum_{i=1}^n x_i$

$\sum_{i=1}^n x_i = n \bar x$

So if the average of all 92 is 7 the sum of those is $92 \times 7$

The average of the last two is 7.2 so their sum is $2 \times 7.2$

That means the sum of the first 90 is $92 \times 7 - 2 \times 7.2$

so the average of the first 90 is

$\dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556$ cm

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3 years ago

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Vlad1618 [11]

Complete Question

Table of Annual CPI values

2003-184.00

2004-188.90

2005-195.3

2006-201.6

2007-207.342

2008-215.303

2009-214.537

2010-218.056

2011-224.939

2012-229.594

2013-232.957

2014-236.736

QRINC offered new employees a starting salary of $34,862 in 2013. What would a comparable starting salary have been in 2003?

Answer:

$C=27535.5881128$

Step-by-step explanation:

From the question we are told that

CPI for 2003(index)=2003-184.00

CPI for 2013(index)=2013-232.957

Starting salary in 2013 at $34,862

Generally comparable starting salary C is given as

$C=\frac{starting salary}{CPI for 2013(index} *CPI for 2003(index)$

$C=\frac{34,862}{232.957} *184$

Therefore C the comparable starting salary is givrn to be

$C=27535.5881128$

$C=27536 appro$

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