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leva [86]
2 years ago
9

Keta Sold tickets for her school play at $s6 for students, and $9 for adults. She sold 15 adult tickets and made a sales total o

f $315. How many student tickets were sold?
Mathematics
1 answer:
kozerog [31]2 years ago
7 0

Answer

Let x be the number of tickets sold to adults and y the number sold to students:

x + y = 315. But we know that y was double x, then :

y = 2x

Plug the value of y (in the 1st equation) by 2x:

x+ 2x = 315

3x = 315

and x = 105 (which is the number of tickets sold to adults

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The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

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Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

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