The perimeter of the larger octagon would be 238 units. This is because the given side is multiplied by 7, so if you do this to all sides and then add them up, you get 238. To check, you can divide 238 by 34 and get 7.
Answer:
Step-by-step explanation:
To find an equation of the sphere with center (4, −12, 8) and radius 10

intersection with xy-plane
Put z=0


(A circle with centre at (4,-12) and radius 6)
intersection with xz-plane
Put y =0


Sum of squares cannot be positive, so DNE
intersection with yz-plane
Put x=0


A circle in YZ plane with centre at y =-12 and z =8 and radius square root of 84
The answer is 78.
54/9 = 6
6x4 = 24
54+24 =78