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aivan3 [116]
2 years ago
15

You look good today, and don’t let people tell you other wise (:

Mathematics
1 answer:
Tamiku [17]2 years ago
5 0

Answer:

Thank You. Have a wonderful day

Step-by-step explanation:

You might be interested in
Help me pls! L need help with this
Sphinxa [80]

Answer:

G. -5/2

Step-by-step explanation:

First we want to distribute the 6 into q and 3.

6q + 18 = 2(q + 4)

Next distribute the 2 into q and 4.

6q + 18 = 2q + 8

Now the variable needs to be on one side of the equation. Subtract 2q from  both sides.

4q + 18 = 8

Isolate the variable. Subtract 18 from both sides.

4q = -10

Divide 4 on both sides.

q = -10/4

We can now simplify this even further. Divide -10/4 by 2/2

q = -5/2

4 0
2 years ago
Consider the equation below. (If you need to use -[infinity] or [infinity], enter -INFINITY or INFINITY.)f(x) = 2x3 + 3x2 − 180x
soldier1979 [14.2K]

Answer:

(a) The function is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) The local minimum is x = 5 and the maximum is x = -6

(c) The inflection point is x = -\frac{1}{2}

(d) The function is concave upward on \left(- \frac{1}{2}, \infty\right) and concave downward on \left(-\infty, - \frac{1}{2}\right)

Step-by-step explanation:

(a) To find the intervals where f(x) = 2x^3 + 3x^2 -180x is increasing or decreasing you must:

1. Differentiate the function

\frac{d}{dx}f(x) =\frac{d}{dx}(2x^3 + 3x^2 -180x) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f'(x)=\frac{d}{dx}\left(2x^3\right)+\frac{d}{dx}\left(3x^2\right)-\frac{d}{dx}\left(180x\right)\\\\f'(x) =6x^2+6x-180

2. Now we want to find the intervals where f'(x) is positive or negative. This is done using critical points, which are the points where f'(x) is either 0 or undefined.

f'(x) =6x^2+6x-180 =0\\\\6x^2+6x-180 = 6\left(x-5\right)\left(x+6\right)=0\\\\x=5,\:x=-6

These points divide the number line into three intervals:

(-\infty,-6), (-6,5), and (5, \infty)

Evaluate f'(x) at each interval to see if it's positive or negative on that interval.

\left\begin{array}{cccc}Interval&x-value&f'(x)&Verdict\\(-\infty,-6)&-7&72&Increasing\\(-6,5)&0&-180&Decreasing\\(5, \infty)&6&72&Increasing\end{array}\right

Therefore f(x) is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) Now that we know the intervals where f(x) increases or decreases, we can find its extremum points. An extremum point would be a point where f(x) is defined and f'(x) changes signs.

We know that:

  • f(x) increases before x = -6, decreases after it, and is defined at x = -6. So f(x) has a relative maximum point at x = -6.
  • f(x) decreases before x = 5, increases after it, and is defined at x = 5. So f(x) has a relative minimum point at x = 5.

(c)-(d) An Inflection Point is where a curve changes from Concave upward to Concave downward (or vice versa).

Concave upward is when the slope increases and concave downward is when the slope decreases.

To find the inflection points of f(x), we need to use the f''(x)

f''(x)=\frac{d}{dx}\left(6x^2+6x-180\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f''(x)=\frac{d}{dx}\left(6x^2\right)+\frac{d}{dx}\left(6x\right)-\frac{d}{dx}\left(180\right)\\\\f''(x) =12x+6

We set f''(x) = 0

f''(x) =12x+6 =0\\\\x=-\frac{1}{2}

Analyzing concavity, we get

\left\begin{array}{cccc}Interval&x-value&f''(x)\\(-\infty,-1/2)&-2&-18\\(-1/2,\infty)&0&6\\\end{array}\right

The function is concave upward on (-1/2,\infty) because the f''(x) > 0 and concave downward on (-\infty,-1/2) because the f''(x) < 0.

f(x) is concave down before x = -\frac{1}{2}, concave up after it. So f(x) has an inflection point at x = -\frac{1}{2}.

7 0
3 years ago
A traveler traveled for 6 hours and covered a distance of 520 km. He traveled the first 260 km by car, and the rest of the way b
Shkiper50 [21]

Answer:

57.78 km/hr

Step-by-step explanation:

Total time taken, t = 6 hours

Total distance covered, d = 520 km

Distance by car = 260

Distance by train = 520 - 260 = 260 km

Train speed = x

Car speed = 2x

Average speed speed = 3x /2

Speed = distance / time

1.5x = 520 / 6

9x = 520

x = 520 / 9

x = 57.777

Average speed of train = 57.78 km/hr

7 0
2 years ago
Which is bigger 80% or 7/9
TEA [102]

Answer:

The number 80% is greater than 7/9.

hope this helps : )

Step-by-step explanation:

7 0
3 years ago
Please help me, eshay lad
AfilCa [17]

Answer:

122.5 cm²

Step-by-step explanation:

Area of this trapezium:

1/2 × 35 × 7

= 245/2 = 122.5 cm²

6 0
2 years ago
Read 2 more answers
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