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3 years ago

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1. A right angled triangle has two shorter sides and one is twice as long as the other. The hypotenuse is 25 cm long. What are t

he lengths of the shorter sides?

1 answer:

Semenov [28]3 years ago

7 0

Step-by-step explanation:

The hypotenuse of a right-angled triangle = 25 cm

One side is twice as long as the other.

Let the other side is x.

First side = 2x

Using Pythagoras theorem to find the lengths of the shorter sides.

$x^2+(2x)^2=25^2\\\\x^2+4x^2=625\\\\5x^2=625\\\\x^2=125\\\\x=11.18\ cm$

So, the other side = 11.18 cm

First side = 2(11.18) = 22.36 cm

So, the lengths of the shorter sides are 11.18 cm and 22.36 cm.

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Answer:

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Step-by-step explanation:

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substituting values

$\sigma_{\= x } = \frac{0.1}{\sqrt{6} }$

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Generally $\frac{X - \mu }{ \sigma_{ \= x }} = Z (The \ standardized \ value \ of \ X )$

So

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substituting values

$P(X < 12) = P ( Z < \frac{12.2 -12 }{0.0408} )$

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