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Mekhanik [1.2K]
3 years ago
12

If 9\geq4x+19≥4x+19, is greater than or equal to, 4, x, plus, 1, which inequality represents the possible range of values of 12x

+312x+312, x, plus, 3?
Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

12x+3\leq 27

Step-by-step explanation:

It is given that

9\geq4x+1

We need to find the possible range of values of 12x+3.

Subtract -1 from both sides.

9-1\geq 4x

8\geq 4x

Multiply both sides by 3.

24\geq 12x

Add 3 on both sides.

24+3\geq 12x+3

27\geq 12x+3

It can be rewritten as

12x+3\leq 27

Therefore, 12x+3 must be less than or equal to 27.

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Step-by-step explanation:

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Part Two:

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