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horsena [70]
3 years ago
6

1. When would a consumer want to use:

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

I think option D

Step-by-step explanation:

HAVE A NICE DAY

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Determine the solution to f(x) = g(x) using the following system of equations:
olya-2409 [2.1K]
In this item, we equate the functions as stated.
             f(x) = g(x)
          3x - 23 = -4.5x + 7

Transpose all the terms with variables to one side of the equation and all the constants to the other side. This is shown below.
         3x + 4.5x = 7 + 23

Combine like terms,
             7.5x = 30
Divide both sides of the equation by 7.5.
            (7.5x)/7.5 = 30/(7.5)
             <em>      x = 4</em>

Therefore, the solution to this item is that x = 4. 
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4 years ago
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3 years ago
Order from least to greatest: 7/12, 0.75, 5/6
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I keep getting confused I don't understand what I keep doing wrong
rosijanka [135]
\bf \begin{cases}&#10;5x+3y+z=-14\\&#10;2x-2y-z=-13\\&#10;3x+y+3z=-2&#10;\end{cases}

so.. let's us eliminate, say "z" first, so for that, let's pick the 1s and 2nd equations there  \bf \begin{array}{llll}&#10;5x+3y+z=-14\\&#10;2x-2y-z=-13\\&#10;----------\\&#10;\boxed{7x+y+0\ =-27}&#10;\end{array}

so, that's our first two-variables resultant

let's pick other two, and again, eliminate the same "z" variable, this time, let's use the 2nd and 3rd equations   \bf \begin{array}{llll}&#10;2x-2y-z=-13&\times 3\implies &6x-6y-3z=-39\\&#10;3x+y+3z=-2\implies &&3x+y+3z\ =-2\\&#10;&&----------\\&#10;&&\boxed{9x-5y+0\ =-41}&#10;\end{array}

now, we have two two-variables equations, let's use them then
and say, we'll eliminate the "y" variable from them

\bf \begin{array}{llll}&#10;7x+y=-27& \times 5\implies &35x+5y=-135\\&#10;9x-5y=-41\implies &&9x-5y=-41\\&#10;&&-------\\&#10;&&44x+0=-176&#10;\end{array}&#10;\\\\\\&#10;x=\cfrac{-176}{44}\implies \boxed{x=-4}&#10;\\\\\\&#10;\textit{now, that we know x = -4, let's plug that in }7x+y=-27&#10;\\\\\\&#10;7(-4)+y=-27\implies y=-27+28\implies \boxed{y=1}

\bf \textit{now, let's plug those two at }5x+3y+z=-14&#10;\\\\\\&#10;5(-4)+3(1)+z=-14\implies -20+3+z=-14\implies z=-14+17&#10;\\\\\\&#10;\boxed{z=3}
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3 years ago
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