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natka813 [3]
3 years ago
10

Here are two column vectors

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0
B Beacuse b best fits the situation
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Someone help me with this ASAP!!!
hjlf

Answer:

95 over 2

because if it is 47 you double that since the denominator is 2 then you add the numerator and now you have your answer.

3 0
3 years ago
Read 2 more answers
A fish jumps out of the water at a speed of 12 feet per second. The height y (in feet) of the fish above the surface of the wate
sasho [114]

Answer:

The fish is 2.25 ft above the surface at 0.375 seconds

Step-by-step explanation:

Given:

y=-16x^2+12x

x=0.375 seconds

Substitute x=0.375 into the equation

y=-16x^2+12x

= -16(0.375)^2 +12(0.375

= -16(0.140625) + 4.5

= -2.25 + 4.5

= 2.25

y=2.25 ft

The fish is 2.25 ft above the surface at 0.375 seconds

8 0
3 years ago
At which root does the graph of f(x)=(x+4)^6(x+7)^5 cross the x-axis ?
Sindrei [870]

Answer:

Step-by-step explanation:

=4

4 0
3 years ago
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A bowling alley charges $2.50 per game plus $4 to rent shoes. A second bowling alley charges $4 per game plus $1 to rent shoes.
adelina 88 [10]

Answer:

The person would have to play 2 games for the two bowling alleys to cost the same amount

Step-by-step explanation:

Assume that the number of games that makes the two costs equal is x

∵ A bowling alley charges $2.50 per game plus $4 to rent shoes

∵ The number of games is x

∴ The cost = 2.50x + 4

∵ A second bowling alley charges $4 per game plus $1 to rent shoes

∵ The number of games is x

∴ The cost = 4x + 1

∵ They have the same cost

→ Equate the 2 expressions above

∴ 4x + 1 = 2.50x + 4

→ Subtract 2.50x from both sides

∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4

∴ 1.50x + 1 = 4

→ Subtract 1 from both sides

∵ 1.50x + 1 - 1 = 4 - 1

∴ 1.50x = 3

→ Divide both sides by 1.50

∴ x = 2

∴ The person would have to play 2 games for the two bowling alleys to

   cost the same amount

7 0
2 years ago
4 divided by 57 please help
Basile [38]

Answer:

0.07017

Step-by-step explanation:

6 0
2 years ago
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