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Elden [556K]
4 years ago
5

Which of the following is something that should not be a consideration when choosing a health care plan? a. annual premiums to b

e paid by the insured individual and family b. deductible or co-pay to be paid by the insured individual and family c. total coverage received by insured individual and family d. the coverage the insured individual and family already receive in auto insurance
Mathematics
2 answers:
timofeeve [1]4 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

i took the test

poizon [28]4 years ago
4 0
<span>im not really sure about this

</span>
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Which ratio forms a proportiona with 5:15?<br><br> A: 10:20<br> B: 75:5<br> C: 3:1<br> D: 1:3
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C

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6 0
3 years ago
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The graph of a quadratic function intercepts the x-axis in two places and the y-axis in one place.
LiRa [457]

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b

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3 years ago
You are going to mix a gallon bucket of window cleaner. The instructions direct you to mix 1 part cleaner to 3 parts water. How
Ira Lisetskai [31]
3 parts water
clean:water=1:3
1:3=xcleaner:1gallon
1/3=xcleaner/1gallon
times 3gallon both sides
1gallon=3xcleaner
divide both sides by 3
1/3 gallon=xcleaner

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7 0
3 years ago
If y=3x^3+x^2-5 and z=x^2-12 what polynomial is equivalent to 2(y+z)
marysya [2.9K]

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2y + 2z

6x³+2x²-10 + 2x²-24

6x³+4x²-34 ■

Step-by-step explanation:

6 0
3 years ago
Determine the equation of the circle graphed below.
sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})

                 =(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)

<u>Find the radius of the circle.</u>

Radius = \frac{Diameter }{2}

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}

               =\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6

Therefore,

    Radius ,r = \frac{6}{2} = 3

<u>Standard equation of a circle:</u>

<u></u>(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.<u></u>

Therefore , equation of the circle ;

                    (x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9

6 0
3 years ago
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