Answer:
5x⁴ + 5x³
Explanation:
We are given that:
f (x) = 5x³
g (x) = x + 1
Now, (f · g)(x) means that we will simply multiply the two functions as follows:
(f · g)(x) = f (x) · g (x)
(f · g)(x) = 5x³ (x + 1)
(f · g)(x) = 5x⁴ + 5x³
Hope this helps :)
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
It would be 9/4. To find 1/3 of something you have to multiply it by 3. 9/4 should be considered as a division expression. Hope this helped!
Answer:
.8 or 4/5ths cup
Step-by-step explanation:
divide number of bottles by cups
4 1/2 is 4.5
5 5/8 is 5.625
4.5/5.625 = .8 (or 4/5ths)
Answer:
23/6
Step-by-step explanation:
3 5/6 multiply 6 times 3 then add 5 which is 23 then take six and is the denominator and 23 is the numerator
