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leva [86]
3 years ago
6

(Giving brainliest to correct answer) Congruence

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:СССР в зеркале

Кто первый спустит курок

​

Убеждаешь - ложно заявляя свободу личности.

Бушующие войны и П-С-О,

​

Космос, О-С-В

Брежнев Рейган

​

Страх оружия С-Я-С

До взаимного уничтожения

Силой и мощью

Союза Советских Республик

Патриоты работают силой порядка

Светлое строят будущее

Наука, Творчество, Семья, Союз,

Образование, Коммуналка, Труд,

Дисциплина, Планировка, Доброта.

​

Родина – поём тебе,

В верности клянёмся,

Пролетарии всех стран Соединяйтесь

​

Серп и Молот!

​

Step-by-step explanation:

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Given the function f(x) = −2x + 8, find x if f(x) = 14 ...?
Over [174]
14 = - 2x + 8
2x = - 6
x = - 3
5 0
3 years ago
Read 2 more answers
Please helpppp meeeee​
aalyn [17]

Answer:

Step-by-step explanation: d I think

7 0
3 years ago
Read 2 more answers
Please help me with this!
stich3 [128]

Answer:

y = x^2 - 4x - 6.

Step-by-step explanation:

The roots are  2 + √10 and 2 - √10, so in factor form we have:

(x -  (2 + √10))(x - (2 - √10))

= ( x -  2 - √10)(x - 2 + √10)

= x^2 - 2x + √10x - 2x + 4 - 2√10 - √10x  + 2√10 - √100

=  x^2 -4x + 4 - 10

= x^2 - 4x - 6.

7 0
3 years ago
Using no digits other than 5 and 8, make a 6-digit number, that has the properties below. If it is impossible, write so. Of cour
Anna11 [10]
Since it's a multiple of 24, it has to be a multiple of the factors of 24.

Factors of 24:
2,3,4,6,8,12

You can use some of this knowledge to help create the number.
Since the # needs to be a multiple off 2, the last digit needs to be an 8

All numbers that are multiples of 3 have the property that all of their digits added together have to be a number that is evenly divisible by 3.

so your number will look like:
_ _ _ _ _ 8

so start trying combinations for the other 5 digits that give you a number that is a multiple of 3: 3,6,9,12,15, ect. If you can't find one, then it's impossible
5 0
3 years ago
With a short time remaining in the​ day, a delivery driver has time to make deliveries at 4 locations among the 7 locations rema
omeli [17]

Answer:

35 different routes

Step-by-step explanation:

The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.

Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.

The number of combinations of n objects taken r at a time is: ⁿCᵣ

So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by

⁷C₄ = 35 different ways.

Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.

Hope this Helps!!!

3 0
3 years ago
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