Preeeeetty sure it's just 16 for that.
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Answer:
90% confidence interval for the true mean weight of orders is between a lower limit of 103.8645 grams and an upper limit of 116.1355 grams.
Step-by-step explanation:
Confidence interval for true mean weight is given as sample mean +/- margin of error (E)
sample mean = 110 g
sample sd = 14 g
n = 16
degree of freedom = n - 1 = 16 - 1 = 15
confidence level = 90% = 0.9
significance level = 1 - C = 1 - 0.9 = 0.1 = 10%
critical value (t) corresponding to 15 degrees of freedom and 10% significance level is 1.753
E = t × sample sd/√n = 1.753×14/√16 = 6.1355 g
Lower limit of sample mean = sample mean - E = 110 - 6.1355 = 103.8645 g
Upper limit of sample mean = sample mean + E = 110 + 6.1355 = 116.1355 g
90% confidence interval is (103.8645, 116.1355)
Answer: 68
Step-by-step explanation:
Formula for sample size when prior estimate of population proportion (p) is available: 
, where z*= critical-value.
E= Margin of error.
Let p be the population proportion of trees are infected with the citrus red mite.
As per given , we have
E= ± 0.08
The critical z-value corresponding to 90% confidence level = z*=1.645
Substitute all the values in the above formula , we get
Required sample size :
[Rounded to next integer.]
Thus, the minimum sample size should be taken =68
Answer:
-(4x + 7)/2 - (3x - 2)/2 = (-4x - 7 - 3x + 2)/2 = (-7x - 5)/2
Answer:
2:3 2:3 3:4 8:7 8:7 3:4 2:3 8:7 3:4
Step-by-step explanation:
