Answer:
In the sample, 61% chose wooden chairs (4% less than that claimed by the company), 24.2% chose plastic chairs (4.2% more than that claimed by the company), and 14.8 % chose metal chairs (0.2% less than what the company claimed). Therefore, given that these are differences of less than 5%, we can affirm that these samples are consistent with what the company said.
Step-by-step explanation:
Given that a large furniture company claims that 65% of all individuals who buy chairs from its stores choose wood chairs, 20% choose plastic chairs, and 15% choose metal chairs, and to investigate this claim researchers collected data from a random sample of the companys customers, whose results were 305 wood, 121 plastic, and 74 metal, to determine if the data from the sample consistent with the companys claim the following calculations should be performed:
305 + 121 + 74 = 500
500 = 100
305 = X
305 x 100/500 = X
30,500 / 500 = X
61 = X
500 = 100
121 = X
121 x 100/500 = X
12,100 / 500 = X
24.2 = X
100 - 61 - 24.2 = X
39 - 24.2 = X
14.8 = X
Therefore, in the sample, 61% chose wooden chairs (4% less than that claimed by the company), 24.2% chose plastic chairs (4.2% more than that claimed by the company), and 14.8 % chose metal chairs (0.2% less than what the company claimed). Therefore, given that these are differences of less than 5%, we can affirm that these are samples that are consistent with what the company said.
Answer:106.38 feet
Step-by-step explanation:
This can be solved by using pythagoras theorem
c=110 feet
b=28 feet
a=?
a=sqrt(110^2-28^2)
=sqrt(12100-784)
=sqrt(11316)
=106.3766 feet
=106.38
Answer:
704π m^2
Step-by-step explanation:
Given data
radius r= 16m
Slant height l= 28m
Required
The surface area of the cone
The expression for the surface area is given as
T.S.A=πrl+πr^2
substitute
T.S.A=π*16*28+π*16^2
T.S.A=448π+256π
T.S.A=704π m^2
Hence the T.S.A is 704π m^2
Please try to be more specific. What I think you meant was "what is the area under the standard normal curve to the left of 2.6 standard deviations above the mean?" If that's it, the area can be found from a table of z-scores (look for z=2.6) or by using a calculator:
normalcdf(-100,2.6) = 0.995.
