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3 years ago

Helppp me pleaseeee!!!!

Mathematics

1 answer:

Pie3 years ago

7 0

Answer:

c,d,f,g

Step-by-step explanation:

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(9x+13)^2=49<br> Solve the quadratic equation given below.

Varvara68 [4.7K]

Answer:

x=(-2/3)

Step-by-step explanation:

(9x+13)^2=49

√(9x+13)^2=√49

9x+13=7

9x+13-13=7-13

9x=-6

9x÷9=-6/9

x=-6/9

-6/9=-2/3

3 0

4 years ago

HELP IM BEING TIMEDDDDDDDDDDDDDDDDDDDDDDD THANK YOU

inysia [295]

Answer:

A + B would be less than A - B

Step-by-step explanation:

6 0

3 years ago

Converting a fraction to a percentage<br> 18/25<br> please include steps

slavikrds [6]

Answer:

72%.

Step-by-step explanation:

We multiply the fraction by 100:

= 100 * 18/25

25 divides into 100 giving 4 so we have:

4 * 18

= 72%.

5 0

3 years ago

Read 2 more answers

(2,15) (-4,-3) in standard form

uranmaximum [27]

Answer:

pizza

Step-by-step explanation:

... :D

7 0

3 years ago

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$

The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

5 0

3 years ago