Question

How Do You Do: 2(n-7)+3=9 And: 4h+7h-16=6

Answer 1

To solve equations with variables, we use inverse operations.
<em />Inverse operations are operations that cancel each other out.
(plus and minus, multiply and divide)

Say we had $x-3=6$.
According to the addition property of equality, we could add 3 to each side of that equation and it would still be equal.
$x-3+3=6+3$
This would cancel out the -3 and leave us with just $x=9$.

Question 1) Solve $2(n-7)+3=9$.

Let's just start cancelling things out. Doesn't matter what order.

$2(n-7)+3=9 \\ 2(n-7)+3-3=9-3\\ 2(n-7)=6 \\\\\ \frac{2(n-7)}2=\frac{6}2\\n-7=3\\\\n-7+7=3+7\\\boxed{n=10}$

Question 2) Solve $4h+7h-16=6$.

You can add $4h$ and $7h$ together to get $11h$. The h acts sort of like a unit in that case, like 4 feet + 7 feet = 11 feet.

$11h-16=6\\11h-16+16=6+16\\11h=22\\\\\frac{11h}{11}=\frac{22}{11}\\\boxed{h=2}$

Answer 2

2 (n-7) +3=9 remove ( ) and distribute 2n-14+3=9 combine like terms 2n-11=9 add 11 to both sides 2n=20 n=10 4h+7h-16=6 combine like terms 11h-16=6 add 16 to both sides 11h=22 h= 2 hope this helps