Step-by-step explanation:
5(tanx)^2 -2 +tanx=0
let tanx=y
5y^2 + y-2=0
y=0.5403 or y= -0.7403
tanx=0.5403
x=arctan(0.5403)
x=28.38°
or
tanx=-0.7403
x=arctan(-0.7403)
x=143.49°
Answer: 7.0596 x 10^2
Explanation: I used a scientific calculator to type in the equation. If you were to type the equation in like that, it'd be 705.96. To covert into scientific notation, you would press the 2nd button, and then press DRG. If you see the options FLO, SCI, and ENG, you want to press SCI, and then you get the answer.
I hope this helps!
1- went up 20%
2- went up 7%
Hope this helps:)
No you have to make sure to line up the decimals when subtracting them. Do not just line of the numbers, this wills get you the wrong answers. Hope this helps. If you need anything else just call for a helping hand.
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
