Answer:
import java.util.Scanner;
public class Main
{
 public static void main(String[] args) {
  Scanner ob = new Scanner(System.in);
  System.out.println("How many numbers? ");
  int n = ob.nextInt();
        int[] arr = new int[n];  
  for (int i=0; i<n; i++) {
      System.out.print("Enter the number: ");
      arr[i] = ob.nextInt();
  }
     System.out.println(indexOfLargestElement(arr));	
 }
 
 public static int indexOfLargestElement(int[] arr) {
     int max = arr[0];
     int maxIndex = 0;
     for (int i=0; i<arr.length; i++) {
         if (arr[i] >= max) {
             max = arr[i];
             maxIndex = i;
         }
     }
     return maxIndex;
 } 
}
Explanation:
Create a method called indexOfLargestElement that takes one parameter, an array
Initialize the max and maxIndex
Create a for loop iterates throgh the array
Check each element and find the maximum and its index
Return the index
Inside the main:
Ask the user to enter how many numbers they want to put in array
Get the numbers using a for loop and put them inside the array
Call the indexOfLargestElement method to find the index of the largest element in the array