Answer:
2. x = 2 & y = 4
3. x = 4 & y = 2
Step-by-step explanation:
2. x + y = 6
2x + y = 8 (multiply the first equation by -1, so you can eliminate the ys)
- x - y = -6
2x + y = 8 (now add the variables together)
x = 2 (plug in x in one of the equations to find out y)
x + y = 6
(2) + y = 6
-2 -2
y = 4
3. 3x + y = 14
x = 2y (plug in x into the first equation and solve it for y)
3(2y) + y = 14
6y + y = 14
7y = 14
y = 2 (plug in y in one of the equations to find out x)
x = 2y
x = 2(2)
x = 4
4. One number (x) is 2 more (+2) than twice (times 2) as large as another. their sum is 17. Find the numbers.
2x + 2 = 17 (solve for x)
-2 -2
2x = 15
x = 7.5
6. 7 (4x + 1) - (x + 6) (start by distributing 7 into the first parenthesis)
(28x + 7) - (x + 6) (do the same to the other parenthesis by distributing -1)
(28x + 7) (-x - 6) (and now just combine like terms)
28x + 7 - x - 6
28x - x + 7 - 6
27x + 1
i hope this helped! if you have any question, pls let me know!
I do not see the letter z in the equation, if there is no mistake the z would be 0
Answer:
4/9
Step-by-step explanation:
<h3>
Answer: 14 feet</h3>
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Explanation:
Check out the diagrams below.
We'll start with the left diagram (marked "before") which is a right triangle with the horizontal leg of 25 feet and hypotenuse 65 feet.
Use the pythagorean theorem to find the vertical side x.
a^2 + b^2 = c^2
25^2 + x^2 = 65^2
625 + x^2 = 4225
x^2 = 4225 - 625
x^2 = 3600
x = sqrt(3600)
x = 60
The top of the ladder is 60 feet high when placed against the wall in this configuration.
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If the upper end is moved down 8 feet, then x-8 = 60-8 = 52 feet is the new height of the ladder. Refer to the "after" in the diagram below.
Like earlier, we'll use the pythagorean theorem to find the missing side.
a^2 + b^2 = c^2
y^2 + 52^2 = 65^2
y^2 + 2704 = 4225
y^2 = 4225 - 2704
y^2 = 1521
y = sqrt(1521)
y = 39
The horizontal distance from the ladder base to the wall is now 39 feet.
Earlier it was 25 feet, so it has increased by 39-25 = 14 feet.