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2 years ago

Evaluate the function -4^3-4(-4)^2+(-4)+7

Mathematics

2 answers:

kumpel [21]2 years ago

8 0

Answer:

-125

Step-by-step explanation:

See image below:)

Furkat [3]2 years ago

4 0

7 ajajajjjajajjajajajajaj

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The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.4 minutes and a standard deviation of 3.5

Lorico [155]

Answer:

0.6672 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.4 minutes

Standard Deviation, σ = 3.5 minutes

We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.

According to central limit theorem the sum measurement of n is normal with mean $\mu$ and standard deviation $\sigma\sqrt{n}$

Sample size, n = 37

Standard Deviation =

$=\sigma\times \sqrt{n} = 3.5\times \sqrt{37}=21.28$

P(taxi and takeoff time will be less than 320 minutes)

$P( \sum x < 320) = P( z < \displaystyle\frac{320 - 37(8.4)}{21.28}) = P(z < 0.4323)$

Calculation the value from standard normal z table, we have,

$P(\sum x < 320) =0.6672 = 66.72\%$

0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

7 0

3 years ago

Which integer is 30 closest to

vesna_86 [32]

Answer:

7,4,15,6

Step-by-step explanation:

7,4,15,6

4 0

2 years ago

Read 2 more answers

The question is:

saul85 [17]

$f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1$

$(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\ \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a$

Therefore, $(fof^{-1})(a) = (f^{-1}of)(a) = a$

8 0

2 years ago

The fraction a/b must be equal to which expression

OlgaM077 [116]

Answer:

Step-by-step explanation:

3 0

2 years ago

Donovan brought 5 1/2 kilograms of flour $8.25

VashaNatasha [74]

A. True, 33/4 × 2/11 = 1,5$
b. False, 8.25÷5.5= 1.5$/kg
c) True

8 0

2 years ago