Answer:
Step-by-step explanation:
1985:
x = 5 years ( 1980 to 1985- 5 years)
0.142x + 1.93 = 0.142*5 + 1.93
= 0.71 + 1.93
= $ 2.64
1999:
x = 19 years
0.142x + 1.93 = 0.142*19+ 1.93
= 2.698 + 1.93
=4.628 = $ 4.63
2010:
x = 30 years
0.142x + 1.93 = 0.142*30 + 1.93
= 4.26 + 1.93
= $ 6.19
The answer on this problem I think it would be 76
If the interest is the same for both accounts then:
.03x=.05(16000-x)
.03x=800-.05x
.08x=800
x=10000, since the interest is the same for both we can just double the interest from one investment to find the total interest earned each year...
.03(10000)2=$600.00
Answer:
a) Sample A
b) Sample D
Step-by-step explanation:
The sample that will provide the most significance evidence for the claim is the one that has the bigger proportion of US citizens who can name the capital city of Canada.
The sample that has the bigger proportion is Sample A, with p=38/40=0.95.
The samples that have a proportion of 0.75 of less surely will give no evidence for the claim.
The sample D has a proportion of p=27/40=0.675, which is less than 0.75, so it doesn't provide evidence for the claim.
Sample C has a proportion of 0.775. Is very close to 0.75, but its value as evidence depends on the level of significance of the test.
theres a thing called a calculator
