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3 years ago

Help me please I need this rn

Mathematics

1 answer:

matrenka [14]3 years ago

6 0

Answer:

p is called transversal

line M and N are called parallel lines

angle 7 and 5 are called vertically opposite angles

angle 2 and 5 are called corresponding angles

Step-by-step explanation:

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Solve the linear system by substitution 3c-2y=16 5x+y=18

andrew11 [14]

It's x or c?
...
...
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6 0

3 years ago

HELP ASAP (MATH)

alexdok [17]

PART - A : tent - 1 volume = 400 cubic ft

Tent -2 volume = 384 cubic ft.

PART - B : I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume

Step-by-step explanation:

PART - A:

tent 1 :

Base = 10 x 10ft

Height= 12 ft

Volume = (1/3) (10x 10) (12)

= (1/3) (100) (12)

= 400 cubic ft.

Tent 2:

Base = 12 x 12 ft

Height= 8 ft.

Volume = (1/3) (12 x 12) (8)

= 384 cubic ft.

PART - B:

I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume

8 0

3 years ago

What’s the class width

aksik [14]

Answer:

Step-by-step explanation:

Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:

CW = UCL - LCL

Where,

CW= Class width

UCL= Upper class limit

LCL= Lower class limit

From the table above:

For class 1, CW = 64 - 60 = 4

For class 2, CW = 69 - 65 = 4

For class 3, CW = 74 - 70 = 4

For class 4, CW = 79 - 75 = 4

For class 5, CW = 84 - 80 = 4

Therefore, the class width of the grouped data = 4

6 0

3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

I dont know how to delete a question

pav-90 [236]

Answer:

use the trash can icon

Step-by-step explanation:I’m pretty sure it’s somewhere you can also get it baNed.

7 0

3 years ago

Read 2 more answers