Answer:
It is 10<em>x</em>^3<em>y</em>
(10x to the third power times y)
Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2
Answer:
First and last option is correct.
Step-by-step explanation:
Given:
There are four options.
(2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2
We need to check all given options for value of 16/81.
Solution:
Using rule.
Solve for option 
.
Solve for option 
.
Solve for option 
.
Solve for option 
.
Therefore, expression and have a value of 
.
Y = -2x + 6
I think this is it
