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professor190 [17]
3 years ago
6

hello please help me, the product of two consecutive odd integers is 399. what equation would be used to solve this problem?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0
A + B = 399
That is the answer
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If the average (arithmetic mean) of five distinct positive integers is 10, what is the difference between the largest possible v
Arte-miy333 [17]

Answer:

The difference between the largest possible value of the greatest integer and the least possible value of the greatest of the five integers = 4

Step-by-step explanation:

<u>Step 1</u>:-

let 'x' be the number

The sequence of arithmetic progression of distinct positive integers

x , x+1 , x+2 , x+3 , x+4

Given the average of five distinct positive integers is 10

\frac{x+x+1+x+2+x+3+x+4}{5} = 10

on simplification , and cross multiplication , we get

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5x +10 =50

subtracting'10' on both sides, we get

5x +10 - 10 = 50 -10

5x =40

dividing '5' on both sides, we get

x = 8

The number is '8'

Step 2:-

Now the arithmetic sequence of five numbers are

x , x+1 , x+2 , x+3 , x+4

8 , 9, 10 , 11 , 12

In this sequence is smallest number is '8' and

The largest number is '12'

the difference between the largest possible value of the greatest integer and the least possible value of the greatest of the five integers

= largest possible value - least possible value

= 12 - 8 =4

<u>Final answer</u> = 4

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Step-by-step explanation:

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