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zvonat [6]
3 years ago
13

Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min

utes and 30 minutes they were at elevations of 10,300 and 10,900 feet, respectively. Write an equation expressing their elevation in relation to time.
Mathematics
1 answer:
kow [346]3 years ago
3 0

Answer:

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, t_1=15 min, the elevation, h_1= 10,300 feet and

at the time t_2= 30 min, the elevation, h_2=10,900 feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let h be the elevation at any time instant t, so the linear relation among these quantities is

h=mt+C_0\;\cdots(i)

where m is the rate of change of elevation with respect to time and C_0 is constant.

The change in the elevation, \Delta h=h_2-h_1= 10,900-10,300=600 feet.

and the change in time, \Delta t=t_2-1_1=30-15=15 min.

So, change in the elevation in unit time,

m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40 feet/min.

Now, from equation (i)

h=40t+C_0

As the elevation, h=h_1 at time t=t_1, so

10,300=40\times15+C_0

\Rightarrow C_0=9700

Hence, the required equation is

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

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