Answer:
x²+y² = 64
Step-by-step explanation:
The standard form of writing the equation of a circle is expressed as;
(x-a)²+(y-b)² = r² where;
(a, b) is the centre of the circle
r is the radius of the circle
Given the diameter of the circle with endpoints (8,0) and (-8, 0)
d = √(x2-x1)²+(y2-y1)²
d = √(-8-8)²+(0-0)²
d = √(-16)²
d = √256
d = 16
radius r = 16/2
r = 8
The centre of the circle will be the midpoint of the coordinates
M = (8-8/2, 0+0/2)
M = (0/2, 0/2)
M = (0,0)
Hence the centre is at (0,0)
Get the required equation
Recall that (x-a)²+(y-b)² = r²
Substitute the centre and the radius
(x-0)²+(y-0)² = 8²
x²+y² = 64
This gives the required equation
