Times both sides b 2
2V=(bh)H
remember associative property
(ab)c=a(bc)
and
ab=ba
so
(bh)H=h(bH)
2V=h(bH)
divide both sides by bH
You're answer is the third one, you gotta divide the money by the hours worked and then compare.
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
In the given question, it is given that, the cost of telephone call, s, is $0.75 plus $0.25 times the number of minutes .
And we have to put the given informationin algebraic expression .
For the cost of telephone call, we have to use s and for the number of minutes, we need to use t .
So the required expression is
If you know what the equation of the line IS(y=mx+b), then you can:
Substitute the x coordinate, slope and y-intercept into the line, then solve for y.
Hope this helped!
