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2 years ago

ANSWER QUICK PLEASE HELP

Mathematics

1 answer:

Zinaida [17]2 years ago

7 0

Equation B is linear. A linear equation will not contain exponents.

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I didn’t do this but my friend needs help so help

yuradex [85]

Answer:

1. X = 14

2.X =13

Step-by-step explanation:

The angles are 90 degrees. I did math to check if the x values are correct and they are.

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2 years ago

Convert 32505 into equivalent number with base 5

velikii [3]

1s -0

5s- 1

25s- 0

125s- 0

625s- 2

3125s- 0

15625s- 2

2020010. I think this is right but would like so confirmation, just taught myself this!

6 0

2 years ago

A above ground garden is rectangular and has a length of 15 feet and a height of 2 feet. It will hold 375 cubic feet of soil. Wh

Fittoniya [83]

Answer: $12.5\ ft$

Step-by-step explanation:

Given

Length L=15 feet

width b=2 feet

Volume V=375 cubic feet

Suppose h is the height

Volume is given by $V=l\times b\times h$

$\Rightarrow 375=15\times 2\times h\\\Rightarrow h=\frac{375}{30}=12.5\ ft$

4 0

2 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.