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Helga [31]
3 years ago
9

Hewwo! ツ

Mathematics
2 answers:
Nuetrik [128]3 years ago
7 0

Answer:

given chord AB=chord CD

L and M are the mid-points of two equal chords AB and CD of a circle

we have

(Equal chords are equidistant from the centre)

In ∆ OLM

OL = OM

<OLM= <OMLbase angles

opposite to equal sides of a A

But <OLA = <OMC(Each = 90°being perpendicular )

On adding

<OLM+<OLA = <OML+<OMC

=<ALM = <CML

Kay [80]3 years ago
5 0

Answer:

Given: chord AB=chord CD

L and M are the mid-points of two equal chords AB and CD of a circle

we have

(Equal chords are equidistant from the centre)

In ∆ OLM

OL = OM

<OLM= <OMLbase angles

opposite to equal sides of a A

<OLA = <OMC(Each = 90°being perpendicular) Adding

<OLM+<OLA = <OML+<OMC

<ALM=<CML

Hence proved.

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